Ultimate Guide to the 1z1-071 - Latest Oct 15, 2024 Edition Available Now
2024 Updated Verified Pass 1z1-071 Exam - Real Questions and Answers
Oracle 1z1-071 exam is an excellent option for individuals who want to improve their career prospects in the database management field. It is also a great opportunity for those who want to enhance their skills and knowledge of SQL. Oracle Database SQL certification is highly valued by employers and can lead to better job opportunities and higher salary packages.
The Oracle 1Z0-071 is a certification exam that proves the candidate’s knowledge of SQL technology and SQL concepts required to participate in any database project. The target audience for this exam is the IT professionals with some experience in working with these technologies. The fundamental knowledge of general computing concepts and command line interfaces will be an advantage as well.
Oracle 1z1-071 exam, also known as the Oracle Database SQL exam, is designed to test the skills and knowledge of professionals who work with Oracle databases. 1z1-071 exam focuses on SQL, or Structured Query Language, which is used to manage and manipulate data in a relational database management system (RDBMS). Passing 1z1-071 exam confirms that the individual has a solid understanding of SQL and can effectively perform tasks such as querying data, creating and modifying database objects, and controlling transactions.
NEW QUESTION # 67
Examine this description of the PRODUCTS table:
Rows exist in this table with data in all the columns. You put the PRODUCTS table in read-only mode.
Which three commands execute successfully on PRODUCTS?
- A. DROP TABLE products;
- B. ALTER TABLE products SET UNUSED (expiry_date);
- C. CREATE INDEX price_idx ON products (price);
- D. ALTER TABLE products DROP COLUMN expiry_date;
- E. ALTER TABLE products DROP UNUSED COLUMNS;
- F. TRUNCATE TABLE products;
Answer: A,C,F
NEW QUESTION # 68
Examine the structure of the EMPLOYEES table.
You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?
- A. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100)UNION ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000);
- B. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;
- C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000;
- D. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE-180;
Answer: C
NEW QUESTION # 69
View the Exhibits and examine the structure of the COSTSand PROMOTIONStables.
You want to display PROD_IDSwhose promotion cost is less than the highest cost PROD_IDin a promotion time interval.
Examine this SQL statements:
What will be the result?
Exhibit 1.
Exhibit 2.
- A. It gives an error because the ALLkeyword is not valid
- B. It executes successfully and gives the required result
- C. It executes successfully but does not give the required result
- D. It gives an error because the GROUP BYclause is not valid
Answer: B
NEW QUESTION # 70
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables. (Choose the best answer.)
You executed this UPDATE statement:
UPDATE
( SELECT order_date, order_total, customer_id FROM orders)
Set order_date = '22-mar-2007'
WHERE customer_id IN
(SELECT customer_id FROM customers
WHERE cust_last_name = 'Roberts' AND credit_limit = 600);
Which statement is true regarding the execution?
- A. It would not execute because a SELECT statement cannot be used in place of a table name.
- B. It would not execute because a subquery cannot be used in the WHERE clause of an UPDATE statement.
- C. It would execute and restrict modifications to the columns specified in the SELECT statement.
- D. It would not execute because two tables cannot be referenced in a single UPDATE statement.
Answer: C
NEW QUESTION # 71
You need to display the first names of all customers from the CUSTOMERStable that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
SELECT cust_first_name
- A. FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name, -2, 1)='a';
SELECT cust_first_name - B. FROM customers
WHERE INSTR(cust_first_name, 'e')IS NOT NULL AND
SUBSTR(cust_first_name, 1, -2)='a';
SELECT cust_first_name - C. FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name, LENGTH(cust_first_name), -2)='a'; - D. FROM customers
WHERE INSTR(cust_first_name, 'e')<>'' AND
SUBSTR(cust_first_name, -2, 1)='a';
SELECT cust_first_name
Answer: A
Explanation:
Explanation
NEW QUESTION # 72
Examine this statement:
Which two statements are true?
- A. The names of employees maximum salary will appear fist to ascending order
- B. All remaining employee names will appear in an ascending order
- C. All remaining employee names will appear in ascending order
- D. The names of employees maximum salary will appear fist to descending order
- E. The names of employees remaining the maximum salary will appear first in an ascending order
- F. All remaining employee names will appear in descending order
Answer: C,D
NEW QUESTION # 73
View and Exhibit and examine the structure and data in the INVOICE table.
Which two statements are true regarding data type conversion in query expressions? (Choose two.)
- A. inv_amt = '0255982' : requires explicit conversion
- B. inv_date > '01-02-2008' : uses implicit conversion
- C. inv_date = '15-february-2008' :uses implicit conversion
- D. inv_no BETWEEN '101' AND '110' : uses implicit conversion
- E. CONCAT(inv_amt, inv_date) : requires explicit conversion
Answer: C,D
NEW QUESTION # 74
Examine the following query:
SQL> SELECT prod_id, amount_sold
FROM sales
ORDER BY amount_sold
FETCH FIRST 5 PERCENT ROWS ONLY;
What is the output of this query?
- A. It displays 5 percent of the products with the highest amount sold.
- B. It displays the first 5 percent of the rows from the SALES table.
- C. It displays 5 percent of the products with the lowest amount sold.
- D. It results in an error because the ORDER BY clause should be the last clause.
Answer: C
Explanation:
Explanation
https://oracle-base.com/articles/12c/row-limiting-clause-for-top-n-queries-12cr1
NEW QUESTION # 75
Examine the data in the CUST_NAME column of the CUSTOMERS table.
You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:
Which two queries give the required output?
- A. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
- B. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',-1,2)<>0;
- C. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
- D. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,-2)<>0;
Answer: A,B
NEW QUESTION # 76
Examine this SELECT statement and view the Exhibit to see its output:
SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output? (Choose two.)
- A. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
- B. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
- C. In the second column, 'c' indicates a check constraint.
- D. The STATUS column indicates whether the table is currently in use.
Answer: B,C
NEW QUESTION # 77
View the exhibit and examine the structure in ORDERS and ORDER_ITEMS tables.
You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATE VIEW statement would create the view successfully?
- A. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id, o.order_date;
- B. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)"NO OF ITEMS"FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date; - C. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_date; - D. CREATE OR REPLACE VIEW ord_vuAS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id)||'NO OF ITEMS'FROM orders o JOIN order_items iON (o.order_id = i.order_id)GROUP BY o.order_id,o.order_dateWHITH CHECK OPTION;
Answer: B
NEW QUESTION # 78
Which two queries return the string Hello! we're ready?
- A. SELECT q'[Hello! We're ready]'FROM DUAL;
- B. SELECT 'Hello! we\ re ready' ESCAPE'N'FROMDUAL:
- C. SELECT "Hello! We're ready "FROM |DUAL;
- D. SELECT 'Hello! We're ready' FROM DUAL;
- E. SELECT q'! Hello! We're ready! 'FROM DUAL;
Answer: A,E
Explanation:
In Oracle SQL, the q quote operator can be used to define string literals that contain single quotes or other special characters without needing to escape them. The queries using the q quote mechanism, like in options A and C, will successfully return the string as it is, including single quotes within the string.
* A: Correct, it uses the q quote operator with the exclamation mark ! as the delimiter, which allows the string to contain single quotes.
* B: Incorrect, double quotes " in Oracle SQL are used for identifiers such as column names, not string literals.
* C: Correct, this also uses the q quote operator, with the square brackets [] as the delimiters.
* D: Incorrect, the backslash \ is not used as an escape character in Oracle SQL string literals, and the ESCAPE keyword is used incorrectly here.
* E: Incorrect, this does not account for the single quote within the string, which would terminate the string literal prematurely, and it lacks the q quote operator or proper escape mechanism.
NEW QUESTION # 79
View the exhibit and examine the structure and data in the invoice table. (Choose two.) Which two SQL statements would execute successfully?
- A. SELECT MAX(AVG(SYSDATE -inv_date)) FROM invoice
- B. SELECT MAX(inv_date), MIN(cust_id) FROM invoice
- C. SELECT AVG(inv_date) FROM invoice
- D. SELECT AVG( inv_date -SYSDATE), AVG(inv_amt) FROM invoice
Answer: B,D
NEW QUESTION # 80
You must display details of all users whose username contains the string 'ch_'. (Choose the best answer.) Which query generates the required output?
- A. SELECT * FROM users
Where user_name LIKE 'ch\_%' ESCAPE '_'; - B. SELECT * FROM users
Where user_name LIKE '%ch\_%' ESCAPE '\'; - C. SELECT * FROM users
Where user_name LIKE '%ch_%'ESCAPE'%'; - D. SELECT * FROM users
Where user_name LIKE '%ch_';
Answer: C
Explanation:
Explanation/Reference:
NEW QUESTION # 81
The ORDERS table has a column ORDER_DATE of date type DATE The default display format for a date is DD-MON-RR Which two WHERE conditions demonstrate the correct usage of conversion functions?
- A. WHERE order_date> TO_DATE(ADD_MONTHS(SYSDATE,6),'MON DD YYYY');
- B. WHERE order_date> TO_DATE('JUL 10 2018','MON DD YYYY');
- C. WHERE order_date IN (TO_DATE ('Oct 21 2018','MON DD YYYY'), TO_CHAR('Nov 21 2018','MON DD YYYY'));
- D. WHERE TO_CHAR(order_date,'MON DD YYYY') ='JAN 20 2019';
- E. WHERE ordet_date> TO_CHAR(ADD_MONTHS(SYSDATE, 6),'MON DD YYYY')
Answer: B,D
NEW QUESTION # 82
Which two are true about scalar subquery expressions? (Choose two.)
- A. You can use them as a default value for a column.
- B. They can return at most one row.
- C. You must enclose them in parentheses.
- D. They can return two columns.
- E. You cannot correlate them with a table in the parent statement.
Answer: B,C
NEW QUESTION # 83
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